Question

The nuclear binding energy of one nitrogen-14 atom is (BLANK) x 10A J. Round to 3

significant digits.

What is the answer to the blank?

Answer 1

The nuclear binding energy per nucleon for a nitrogen-14 atom is 8.79 MeV/nucleon.

Step-by-step explanation:

The nuclear binding energy of one nitrogen-14 atom can be calculated by dividing the total nuclear binding energy by the number of nucleons in the nucleus. In this case, the total nuclear binding energy is 492 MeV and the number of nucleons is 56. So, the binding energy per nucleon for the nitrogen-14 atom is 492 MeV/56 nucleons = 8.79 MeV/nucleon.

Answer 2

mass defect = mass of constituents - mass of atom

N has 7p and 9n

proton mass ~ 1.00728 amu

neutron mass ~ 1.00866 amu

electron mass ~ 0.000549 amu

Nitrogen mass ~ 14.003074 amu

mass defect = (7*1.00728)-(7*1.00866)-(7*0.000549) - 14.003074

= 0.11235amu

convert to energy, the binding energy = 1.68x10^-11 J