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4 votes
(((4^2-(7×2))^4×2)-2)÷3+(5×2)÷2-5

User Jbww
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1 Answer

3 votes

So for eyes' sake, I will be using different brackets to read the equation better. Here's how to solve this expression:


(\{[4^2-(7*2)]^4*2\}-2)/ 3+(5*2)/ 2-5\\ (\{[16-14]^4*2\}-2)/ 3+10/ 2-5\\ (\{2^4*2\}-2)/ 3+5-5\\ (\{16*2\}-2)/ 3+5-5\\ (32-2)/ 3+5-5\\ 30/ 3+5-5\\ 10+5-5\\ 10

The answer is 10.

User Jason Wells
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5.1k points