Answer:
Yes
Explanation:
Since, it is a graph in polar coordinates, So we can start with the base equation of this given equation which should be:
![r = cos(theta)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/e6rlyse6hmh5oulaosjet6vd4ckpoe5hik.png)
and its graph is a circle with centre at (0.5,0), if we multiply it by 2, then its radius will be doubled and it will become:
![r =2 cos(theta)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/g7blsjdc85xxs355gmq0k36rgbgm4bdyrs.png)
Thus, giving a circle of radius 1. If we multiply it by -1, then:
![r =-2 cos(theta)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fg275q7y4jx02krw91cu5gv5steehp5wyd.png)
It will give us a circle shifted 1 units to the left. If we add 3 in it, we will get a cardioid which is passing through y = 3 and y = -3 at x = 0,
![r =3-2 cos(theta)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vdpkp39sxfsli8pxa1j4ew5a4xizmhfxar.png)
And this graph will be a symmetric graph about the x-axis. Hence the answer is Yes.