Question

How do I solve this problem

Answer 1

`9p > 63\ \ \ \ |:9\\\\p > 7\\--------------\\\\(p)/(3)\leq2\ \ \ \ |\cdot3\\\\p\leq6`

Answer:

On the picture.

`p\in(-\infty;\ 6]\ \cup\ (7,\ \infty)`

Answer 2

`\bf 9p>63\implies p>\cfrac{63}{9}\implies \boxed{p>7}\\\\\\\cfrac{p}{3}\le 2\implies \boxed{p\le 6}`

check the picture below.