Question

What is the value of work done on a object when a 10-newton force moves it 30 meters and the angle between the force and displacement is 25degrees

Answer 1

Hello


`\bold{w = Fs*cos\theta}`

→ w = 10*30*cos25°

cos25° = 0.991203

→ Work Done = 297.360 Joule ( J )

Hope It helps You. ^_^