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What is the value of work done on a object when a 10-newton force moves it 30 meters and the angle between the force and displacement is 25degrees
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What is the value of work done on a object when a 10-newton force moves it 30 meters and the angle between the force and displacement is 25degrees

User Alexander Gonchiy
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Hello


\bold{w = Fs*cos\theta}

→ w = 10*30*cos25°

cos25° = 0.991203

→ Work Done = 297.360 Joule ( J )

Hope It helps You. ^_^
User Takumi
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