Question

Find the equation of a line that goes through points (-3, -5) and (-1, -2).

Answer 1

The slope-point formula:

`y-y_1=m(x-x_1)`

The formula of a slope:
`m=(y_2-y_1)/(x_2-x_1)`

We have:

`(-3,-5)\to x_1=-3,\ y_1=-5\\(-1,-2)\to x_2=-1,\ y_2=-2`

Substitute and calculate:

`m=(-2-(-5))/(-1-(-3))=(3)/(2)=1.5\\\\y-(-5)=1.5(x-(-3))\\\\y+5=1.5(x+3)\\\\y+5=1.5x+4.5\ \ \ |-5\\\\y=1.5x-0.5`