Question

How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?

Answer 1

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

hope this helps!