223k views
1 vote
A punter kicks a football upward with an initial speed of 48 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed

User Av Pinzur
by
8.0k points

2 Answers

0 votes

check the picture below. That's pretty much a rough graph of an initial speed scenario.


so, we know the ball will hit the ground when h = 0, and we know that r = 48, thus



image

A punter kicks a football upward with an initial speed of 48 feet per second. After-example-1
User Dixon
by
8.3k points
6 votes

Answer:

3 seconds.

Explanation:

We have been given that a punter kicks a football upward with an initial speed of 48 feet per second. Use the formula
h=rt-16t^2 to find after how many minutes ball will hit the ground.

The ball will hit the ground, when height, h equals to 0.


h=48t-16t^2


0=48t-16t^2


-16t^2+48t=0


-16t(t-3)=0

Using zero product property, we will get:


-16t=0\text{ or }(t-3)=0


t=0\text{ or }t-3=0


t=0\text{ or }t=3

Therefore, after 3 seconds ball will hit the ground.

User Erikreed
by
9.5k points