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AREA ADDITION AND SUBTRACTION URGENT?

AREA ADDITION AND SUBTRACTION URGENT?-example-1
User Lukegf
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1 Answer

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We can find the area of the segment by subtracting the area of the triangle (A_triangle) from the area of the sector (A_sector).

A_segment = A_sector - A_triangle

We then find the value of each variable. For the sector of the circle, we use the equation: A_sector = (angle/360)(pi*r^2)

Plugging in the values we will have

A_sector = (68.9/360)(pi*9.28^2) = 51.8

Now for the triangle, area is simply 1/2 * base * height. Since two sides of the triangle have the radius as the angle, and the angle between them given, we then use the formula A_triangle=1/2ab(sin C). Where in C is the given angle, and a and b are the corresponding sides.

A_triangle = (1/2)(9.28)(9.28)(sin 68.9)

A_triangle = 40.2

All that is left for us is to subtract the triangle area from the sector area.

A_segment = 51.8 - 40.2

A_segment = 11.6 square centimeters

User Zach Hirsch
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