Question

How many moles of oxygen are in 3.7 moles of C8H11O2

Answer 1

To find the moles of oxygen in 3.7 moles of C8H11O2, simply multiply the number of moles of the compound by two, as there are two oxygen atoms in each molecule of C8H11O2. This results in 7.4 moles of oxygen.

Step-by-step explanation:

To determine how many moles of oxygen are in 3.7 moles of C8H11O2, we consider the molecular formula of the compound. The molecular formula indicates that for each mole of C8H11O2, there are two moles of oxygen. Therefore, if you have 3.7 moles of C8H11O2, you have twice as many moles of oxygen.

Moles of O in C8H11O2 = moles of C8H11O2 × 2
Moles of O in C8H11O2 = 3.7 moles × 2 = 7.4 moles of oxygen

Hence, there are 7.4 moles of oxygen in 3.7 moles of C8H11O2.

Answer 2

Given: Molecular formula of the compound is C₈H₁₁O₂

Since C₈H₁₁O₂ molecule contains two atoms of oxygen which is equal to one mole.

∵ In 1 mole of C₈H₁₁O₂, oxygen has = 1.0 mole

∴ In 3.7 moles of C₈H₁₁O₂, oxygen has = (1.0 mole) × (3.7 moles) ÷ (1 mole)

= 3.7 moles

Hence, oxygen has 3.7 moles in 3.7 moles of C₈H₁₁O₂