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Find the following product ^5 square root 4x^2* ^5 square root 4x^2?

1) 4x^2
2) ^5sqrt 16x^4
3) 2(^5sqrt 4x^2)
4) 16x^4

User Bene
by
8.7k points

2 Answers

3 votes

Answer:

b

Explanation:

User LVB
by
7.9k points
2 votes

I'm assuming that you're asking about


\sqrt[5]{4x^2}\cdot\sqrt[5]{4x^2}

If this is the case, you need to use the following rule:


\sqrt[a]{b}\cdot\sqrt[a]{c} = \sqrt[a]{bc}

In other words, if the roots have the same order, the multiplication of the roots is the same thing as the root of the product of their content.

So, we have


\sqrt[5]{4x^2}\cdot\sqrt[5]{4x^2} = \sqrt[5]{4x^2 \cdot 4x^2} = \sqrt[5]{16x^4}

User Mtk
by
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