173k views
2 votes
CONDITIONAL PROBABILITY ASSISTANCE?

CONDITIONAL PROBABILITY ASSISTANCE?-example-1
User Shahidur
by
8.6k points

1 Answer

4 votes

WE need to find the probability (
(Junior)/(girl))

We know Probability (
(A)/(B)) =
(P(A and B))/(P(B))

P (
(Junior)/(Girl)) =
(P(Junior and girl))/(P(girl))

First we find P(Girl)

From the table we can see that we have 18 girls out of (12+18=30) students

So P(Girl) =
(18)/(30)

Now we find the intersection of Junior and Girl

WE look at the Junior row and girls column that is 3

{P(Junior ∩ Girl) =
(3)/(30)

P (
(Junior)/(Girl)) =
(P(Junior and girl))/(P(girl))

P (
(Junior)/(Girl)) =
((3)/(30))/((18)/(30))

=
(3)/(18) = (1)/(6)

User Sandesh Sapkota
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories