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Find the velocity of the student using KE= 1/2 mv^2. A 50-kilogram student is running and has 225 joules of kinetic energy. The student’s speed is meters/second

User DNNX
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2 Answers

7 votes

Answer:

A 50-kilogram student is running and has 225 joules of kinetic energy. The student’s speed is

3

meters/second.

Step-by-step explanation:

User Huang Jinlong
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3 votes
225 = 1/2 (50) (v2)
225 = 25 (v2)
225/25 = v2
9 = v2
√9 = v
v = 3 m/s
User Chesky
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