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Suppose a merry-go-round is spinning once every 3 seconds. If a point on the outside edge has a speed of 12.56 feet per second, what is the radius of the merry-go-round? (Use 3.14 for pi)
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Suppose a merry-go-round is spinning once every 3 seconds. If a point on the outside edge has a speed of 12.56 feet per second, what is the radius of the merry-go-round? (Use 3.14 for pi)

User Ldsenow
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all you have do is divide 3.14 by 3 which =1.04

ANSWER =1.04

User Lea Rosema
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