77.2k views
0 votes
In a quadrilateral MNOP the length of side MN is (4x − 7) units and the length of side ON is (7 − 3x) units. What value of x will make it a rhombus?

14
2
7
12

User Yort
by
6.4k points

1 Answer

2 votes

In a rhombus, all sides are equal.

So for the quadrilateral MNOP to be a rhombus, the given sides have to be equal. THat is


MN=ON


image

Adding 3x to both sides and addinf 7 to both sides


7x = 14

Now we need to get rid of 7 and for that we do division, that is


(7x)/(7) = (14)/(7)


x=2

Correct option is the second option .

User Haris N I
by
7.6k points