Question

Evaluate P(3,3) help please

Answer 1

`P(n,k)` where
`n=k` is equal to
`n!`

So,
`P(3,3)=3!=6`

Generally,
`P(n,k)=(n!)/((n-k)!)`

Answer 2

The value of P(3,3) is 6

Explanation:

We have to evaluate P(3,3)

As permutation can be calculated by the formula

`P(n,r)=_r^n\txterm{P}=(n!)/((n-r)!)`

`P(3,3)=_3^3\txterm{P}=(3!)/((3-3)!)`

`=(3!)/(0!)=(3!)/(1)=3* 2* 1=6`

Hence, the value of P(3,3) is 6