Cr2O3(s) + 2Al(s) ----> 2Cr(s) + Al2O3(s)
Cr⁺³ +3e⁻ -------> Cu⁰ - oxidizing agent
Al⁰ -------> Al⁺³ + 3e⁻ - reducing agent
Answer:
The oxidizing agent is: Cr, cr
The reducing agent is: Al, al
Step-by-step explanation:
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