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Which are the correct solutions

Which are the correct solutions-example-1
User Hzap
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2 Answers

4 votes

We'll do this last last one real slow.


x^2 + 10 x + 25 = 8

Step one, move the 8 to the left side by subtracting it from 25:


x^2 + 10x + 17 = 0

To factor we'd need factors of 17 which add to 10. The only factors of 17 are 17 and 1 so there's no factoring. We use the quadratic formula.


x= \frac 1 {2a}(-b \pm √(b^2-4ac))

a, b and c refer to the coefficients on the quadratic equation. We have
x^2 + 10 x + 17 = 0 so a=1 (the coefficient on x^2) b=10, c=17.


x= \frac 1 2(-10 \pm √(10^2-4(17)))

Now we simplify the square root. 10²=100, 4(17)=68, so


x = \frac 1 2(-10 \pm √(32))

32 = 16(2) so we can simplify a bit more.


x = \frac 1 2(-10 \pm 4 √(2))


x = -5 \pm 2 √(2)

We compare to the answers and get

Answers: A E

With the Shakespeare Quadratic Formula shortcut


x^2-2bx+c \textrm{ has zeros } x=b \pm √(b^2-c)

Using that on
x^2 + 10x + 17 = 0 we could have gotten here a bit quicker. b=-5 this time, c=17, so


x=-5 \pm √(25-17) = -5 \pm \sqrt 8 = -5 \pm 2 \sqrt 2

Good luck. Please ask questions if you're still unsure.

User Evans
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5.1k points
4 votes
The factors are ( -5+2root2 , -5-2root2 )
Which are the correct solutions-example-1
User Thexfactor
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5.0k points