We'll do this last last one real slow.
![x^2 + 10 x + 25 = 8](https://img.qammunity.org/2019/formulas/mathematics/middle-school/nbyasz1w8m2ec2stsu5on9fc5pgjwu90uh.png)
Step one, move the 8 to the left side by subtracting it from 25:
![x^2 + 10x + 17 = 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zcuaekm7hjc2gdq1kmfc0tunkpei979xaj.png)
To factor we'd need factors of 17 which add to 10. The only factors of 17 are 17 and 1 so there's no factoring. We use the quadratic formula.
![x= \frac 1 {2a}(-b \pm √(b^2-4ac))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ijzy85b4ph6xtufwwdkh4fnjdnsv9y78o7.png)
a, b and c refer to the coefficients on the quadratic equation. We have
so a=1 (the coefficient on x^2) b=10, c=17.
![x= \frac 1 2(-10 \pm √(10^2-4(17)))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/tctys64vaswaodff0fe5gzd51y7es9gkt1.png)
Now we simplify the square root. 10²=100, 4(17)=68, so
![x = \frac 1 2(-10 \pm √(32))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zkw64k8kmqgdqy6djyt6ukyivii9uhsqma.png)
32 = 16(2) so we can simplify a bit more.
![x = \frac 1 2(-10 \pm 4 √(2))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/78l3hcz7u8v7lmmo4mqjtrcc0xf1of1g9a.png)
![x = -5 \pm 2 √(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/f2kwyq4sz21rgzq2qzezp4yfy4zw1ou4q9.png)
We compare to the answers and get
Answers: A E
With the Shakespeare Quadratic Formula shortcut
Using that on
we could have gotten here a bit quicker. b=-5 this time, c=17, so
![x=-5 \pm √(25-17) = -5 \pm \sqrt 8 = -5 \pm 2 \sqrt 2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kgt94u5j61rbdxegyomeu95ikk1vi428x9.png)
Good luck. Please ask questions if you're still unsure.