Question

Which equation has the solutions (x=-3=/- square root of 3i) / 2

Options:

2x2 + 6x + 9 = 0

x2 + 3x + 12 = 0

x2 + 3x + 3 = 0

2x2 + 6x + 3 = 0

Answer 1

c- x2 + 3x + 3 = 0

Explanation:

Answer 2

we are given

solution of quadratic equation as

`x=(-3+-√(3)i)/(2)`

we can also write it as

`x=(-3-√(3)i)/(2)`

`x=(-3+√(3)i)/(2)`

now, we can write it in terms of function

`f(x)=(x-((-3+√(3)i)/(2)))(x-((-3-√(3)i)/(2)))`

Firstly , we can multiply it

`=xx-\left((-3-√(3)i)/(2)\right)x-\left((-3+√(3)i)/(2)\right)x+\left((-3+√(3)i)/(2)\right)\left((-3-√(3)i)/(2)\right)`

`x^2+3x+(9)/(4)-(3i^2)/(4)=0`

now, we can simplify it

`x^2+3x+(9)/(4)+(3)/(4)=0`

`x^2+3x+(12)/(4)=0`

`x^2+3x+3=0`

so,

option-C.........Answer