Question

If the brakes are applied and the speed of the car is reduced to 12 m/s in 15 s , determine the constant deceleration of the car.

Answer 1

Given:

`\triangle v` = 12 m/s

Time = 15 s

To find:

Deceleration = ?

Formula used:

Deceleration is given by,

a =
`(\triangle v)/(t)`

Solution:

Acceleration of the body is rate of increase of velocity. Deceleration of the body is negative acceleration i. e rate of decrease of velocity.

Thus, deceleration of the body is given by,

a =
`(\triangle v)/(t)`

where a is the deceleration of the body

v is the velocity

`(\triangle v)/(t)` is rate of change of velocity

t is the time

a =
`(12)/(15)`

a = 0.8 m/
`s^(2)`

Thus, deceleration is 0.8 m/
`s^(2)`.