Let us consider the second number would be
![](https://img.qammunity.org/2019/formulas/mathematics/middle-school/x9fblrh5ruk5yia1vsf9r12onov5p9fqze.png)
The first number is eight more than the second one.
That is, the first number would be
" src="
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p6f1uoc27axp3way37npy8nbfd9s6i9p44.png)
Three times the second number would be
![](https://img.qammunity.org/2019/formulas/mathematics/middle-school/razz3e25g4790ic46gz9axo42g31417gfm.png)
Twice the first number would be
![](https://img.qammunity.org/2019/formulas/mathematics/middle-school/j9hab6gx6oaqq521h6w18bpz4rleqlm1zi.png)
Now write the statement in mathematical form: "Three times the second number plus twice the first number is equal to 26"
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7rndout5h1neh6g6yo6noifmf5gyzfhp1j.png)
Solve this equation for x:
Distribute 2 in
, we get
![3x+2x+16=26](https://img.qammunity.org/2019/formulas/mathematics/middle-school/92riye4ops2ju1k3th7s1nbjo2dfnm32mz.png)
Combine the like terms,
![5x+16=26](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zzoclesjlgbiv0diahb1z27vzvrybl6auj.png)
Subtracting 16 on both sides,
![5x+16-16=26-16](https://img.qammunity.org/2019/formulas/mathematics/middle-school/e2nt2clmf9dtyr7z3ttd9751hojg3yfsfx.png)
![5x=10](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qekpxedws0hlbu5dmbeluv02h6gd6mpnhu.png)
Dividing 5 on both sides,
![x=10/5=2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/w30zfvcosykv348unwxbp2etdeoau1fuyt.png)
So the second number is
![x=2.](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zd18upk6x81qewcnw1nb27ndzc4257zdce.png)
Now find the first number:
First number
![= x+8=2+8=10.](https://img.qammunity.org/2019/formulas/mathematics/middle-school/rpilczrer72m8h6gxbph410qa27pq2aqdv.png)
Thus the numbers are 10 and 2.