Question

Please help right away.

Answer 1

`f(x)=(x^2-4)/(x^2-6x+8)=(x^2-2^2)/(x^2-4x-2x+8)=((x-2)(x+2))/(x(x-4)-2(x-4))\\\\=\frac{\boxed{(x-2)}(x+2)}{\boxed{(x-2)}(x-4)}\to x=2\\\\g(x)=(x+2)/(x-4)\to g(2)=(2+2)/(2-4)=(4)/(-2)=-2\to y=-2\\\\\text{Answer:}\ b.\ (2,\ -2)`