Question

Plz help! ASAP! What is the expression shown below

Answer 1

we are given

`(1)/(2) ((3)/(2) x+6x+1)-3x`

step-1: Simplify expression inside parenthesis

we will combine like terms

so, firstly we will take common denominator

`(1)/(2) ((3)/(2) x+(2*6)/(1*2)x+1)-3x`

`(1)/(2) ((3x+12x)/(2) +1)-3x`

`(1)/(2) ((15x)/(2) +1)-3x`

step-2: Distribute 1/2 inside

`=(1)/(2) *(15x)/(2) +1*(1)/(2)-3x`

`=(15x)/(4) +(1)/(2) -3x`

step-3: Combine like terms

`=(15x)/(4)+3x +(1)/(2)`

We can find common denominator

`=(15x)/(4)-(4*3x)/(4*1) +(1)/(2)`

`=(15x)/(4)-(12x)/(4) +(1)/(2)`

`=(15x-12x)/(4) +(1)/(2)`

`=(3x)/(4) +(1)/(2)`

we can also write it as in mixed form

`=(3)/(4)x +(1)/(2)`

so, we will get

`(1)/(2) ((3)/(2) x+6x+1)-3x=(3)/(4)x +(1)/(2)`

option-C.............Answer