Question

Find the values of a and b in the rhombus below.

Answer 1

Since,ABCD is a rhombus =>diagonals bisect each other at 90
b=26. (In a rhombus all sides are parallel)
To find a
In triangle, ABD
Angel ADB=26. ( base angle ppty)
=> Angel a=26+26+a=180. ( angle sum ppty of a triangle)
=>a=180-52=128
Hope this helps u...!!

Answer 2

Hello,

b = 26°
( 26° × 2 ) + 2a = 360°
52° + 2a = 360°
2a = 360° - 52° = 308°
a = 308° / 2 = 154°