Question

PLEASE HELP AND HURRY

solve the following exponential decay function for y when x=3. round to the nearest tenth.

y=(3/4)^x

Answer 1

Here the given expression is

`y =((3)/(4))^x`

We need to find the value of y when x =3 . So we substitute the value of x in the given expression.

`y =((3)/(4))^3 = (27)/(64) =0.4`

So when x=3, y=0.4 and that's the required answer.