Answer: -
4C₂H₅ + 13 O₂ → 8 CO₂ + 10 H₂O
Explanation: -
The given equation is
C₂H₅ + O₂ → CO₂ + H₂O
Balancing for H,
2C₂H₅ + O₂ → CO₂ + 5H₂O
Balancing for C
2C₂H₅ + O₂ → 4CO₂ + 5H₂O
Now right hand side we are getting 13 O which is an odd number.
In order to balance O, we first try to even out the number of O on right side by multiplying whole equation by 2.
4C₂H₅ + 2O₂ → 8CO₂ + 10H₂O
Now balancing for O
4C₂H₅ + 13 O₂ → 8 CO₂ + 10 H₂O