Question

How many moles of NaCl are contained in 100.0 mL of a 2.0 M solution?

Answer 1

Answer: -

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution

Explanation: -

Strength of NaCl = 2.0 M

Volume of NaCl solution = 100.0 mL

=
`(100)/(1000)`

= 0.1 L

Number of moles of NaCl = volume of NaCl x Strength of NaCl

= 0.1 L x 2.0 M

= 0.2 moles

0.2 moles of NaCl are contained in 100.0 mL of a 2.0 M solution