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Find two numbers whose difference is 180 and whose product is a minimum

User Morphasis
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Let the numbers are x and y

And it is given that the difference is 180

So we have


x-y=180


x = 180+y

And let the product is p. So we have


p = xy

Substituting the value of x , we will get


p = y(180+y) = 180y +y^2

Differentiating p,


p'= 180+2y

Again differentiating ,


p'' = 2>0

SO we will get minimum.

And to find the minimum, we have to set p' equal to 0 and solve for y.


180+2y=0 =>y=-90

Back substituting the value of y, we will get


x =180+(-90)


x =90

So the numbers are 90 and -90 .

User Tiffanie
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