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Let , (-2,3) be a point on the terminal side of θ . find the exact values of sinθ , secθ , and tanθ .

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Here we have to use the following ratio rule


tan \Theta =(y)/(x)

In the given point , x=-2, y=3, so


tan \Theta =- (3)/(2)


sec \theta = √(1+tan^2 \theta)

Using the value of tan theta, we will get


sec \theta = -\sqrt{1+(9)/(4)} = -(√(13))/(2)

Now we need to find the value of cos theta


cos \theta = -(1)/(sec \theta) = -(2 √(13))/(13)

And


sin \theta = √(1-cos^2 \theta) = \sqrt{1-(4)/(13)} =(3 √(13))/(13)

User Eugene Bulkin
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