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A parking lot charges $3 to park a car for the first hour and $2 per hour after that. If you use more than one parking space, the second and each subsequent car will be charged 75% of what you pay to park just one car.If you park 3 cars for t hours, which function gives the total parking charge?


A. f(t) = 3(3 + 2(t − 1))

B. f(t) = (3 + 2t) + 0.75 × 2(3 + 2t) C. f(t) = (3 + 2(t − 1)) + 0.75 × 2(3 + 2(t − 1)) D. f(t) = (3 + 2t) + 0.75(3 + 2t) + 0.75 × 0.75(3 + 2t) E. f(t) = (3 + 2(t − 1)) + 0.75(3 + 2(t − 1)) + 0.75 × 0.75(3 + 2(t − 1))

1 Answer

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Given, a parking lot charges $3 for first hour and $2 per hour after that.

So for t hours, the parking lot charges $3 for the first hour and after first hour there is
(t-1) hours left.

So for
(t-1) hours it will charge $2 per hour.

The charges for
(t-1) hours = $
2(t-1).

Total charges for t hours for one car = $
(3+2(t-1))

Now for the second car, it will charge 75% of the first car.

So the charges for second car

=$[
(3+2(t-1))(75/100)]

=$
0.75(3+2(t-1))

There are 3 cars. That parking charges for the third car is also 75% of the first car.

So for third car the parking charges are same as for the second car.

Total parking charges for 3 cars

= $
(3+2(t-1))+(0.75(3+2(t-1))+(0.75(3+2(t-1))

= $
(3+2(t-1))+(0.75)(2(3+2(t-1))

We have got the required answer here.

The correct option is option C.

User Twalthr
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