Question

A game spinner has regions numbered 1 through 9. If the spinner is used twice, what is the probability that the first number is 3 and the second is a 6?

Answer 1

Hello!

As this is a compound event (is made up of two events), we multiply our two probabilities to find the final probability.

First of all, we have a 1/9 chance of getting a 3, and then another 1/9 chance of getting a 6. Therefore, we multiply.

`(1)/(9) ((1)/(9) )=(1)/(81)`

Therefore, we have a 1/81 or about 1.2% chance of this event occurring.

I hope this helps!

Answer 2

The answer is
`(1)/(81)`

Explanation:

Lets assume the spinner is fair spinner.

On the first spin, the probability of any specific number from 1 to nine inclusive is 1/9.

During the second spin, the same value of probability will apply.

The two probabilities are independent of each other.

Hence, the probability that the first number is 3 and the second is a 6 is given by :

`(1)/(9)* (1)/(9) =(1)/(81)`