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Write the standard equation of the circle in the graph.

Question 17 options:

(x + 3)2 + (y – 2)2 = 18

(x + 3) + (y – 2) = 9

(x – 3)2 + (y + 2)2 = 18

(x – 3)2 + (y + 2)2 = 9

Write the standard equation of the circle in the graph. Question 17 options: (x + 3)2 + (y-example-1
User Kal
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8.2k points

2 Answers

3 votes

Answer:

the correct answer I'ds D

User Nmore
by
7.8k points
4 votes
Hi there!

Let's solve this problem step by step!

1. First we take a look at the circle in the graph.

The centre of the circle is located at the point (3, -2). The circle touches the vertical axis in the point (0, -2). We can therefore conclude that the radius of the circle is 3.

2. The general equation of a circle is as follows:

(x - a) {}^(2) + (y - b) {}^(2) = r {}^(2)

In this equation, the point (a, b) is the centre of the circle and r represents its radius.

3. Combine our knowledge from 1. and 2.
Let's substitute the centre and radius into our eqiation!


(x - 3) {}^(2) + (y - - 2) {}^(2) = {3}^(2)
Now we can square on the left side, and replace the two minus signs by a plus.


(x - 3) {}^(2) + (y + 2) {}^(2) = 9
Hence, the answer is D.
~ Hope this helps you!
User Hayley
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8.3k points

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