Question

A 6.00-μf parallel-plate capacitor has charges of 40.0 μc on its plates. how much potential energy is stored in this capacitor?

Answer 1

Thew energy stored in a capacitor of capacitance
`C` and voltage between the plates
`V` is

`E=(1)/(2) CV^2=(1)/(2C) Q^2`.

Substituting numerical value

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