Question

Graph the equations to solve the system.

y=1/2x-1

2y=x-2

Answer 1

`y=(1)/(2)x-1\\\\for\ x=0\to y=(1)/(2)(0)-1=-1\to(0,\ -1)\\\\for\ x=2\to y=(1)/(2)(2)-1=0\to(2,\ 0)`

`2y=x-2\ \ \ \ |:2\\\\y=(1)/(2)x-1!!!`

`\text{Both equations are identical. The solution is:}\\\\\left\{\begin{array}{ccc}x\in\mathbb{R}\\y=(1)/(2)x-1\end{array}\right`