Question

Find the electric field at a point 20cm from a charge of 20micro farads

Answer 1

Electric field due to a point charge is given by

`E = (kq)/(r^2)`

here given that

`k = 9*10^9`

`q = 20\mu C`

`r = 20 cm = 0.20 m`

Now electric field is given by

`E = (9*10^9 * 20 * 10^(-6))/(0.20^2)`

`E = 4.5 * 10^6 N/C`