Given
A person counted 60 steps going up an up-escalator, and 90 steps going down the same up-escalator.
Find
The number of steps she would count if the escalator were standing still.
Solution
This is perhaps the long way around, but we get there.
Define the following variables:
![\begin{array}{rl}d&\text{steps between floors}\\w&\text{walking rate, steps per minute}\\e&\text{escalator rate, steps per minute}\\tu&\text{time it takes to go up the escalator, minutes}\\td&\text{time it takes to go down the escalator, minutes}\end{array}](https://img.qammunity.org/2019/formulas/mathematics/high-school/2rwig8teql3uzzia9b3aqemerkeg6d08qi.png)
The rate at which the steps of the distance d are traversed is w+e (going up) or w-e (going down). The number of steps counted is the rate at which steps are walked (w) multiplied by the time spent going up or down. We can write 4 equations in the 5 unknowns.
![w\cdot tu=60\\w\cdot td=90\\d=(w+e)tu\\d=(w-e)td](https://img.qammunity.org/2019/formulas/mathematics/high-school/zyhp4iyzvzlmgoo71nyyrkrl7ahaxhz02a.png)
Dividing the second by the first, we have
![(w\cdot td)/(w\cdot tu)=(90)/(60)\\\\ (td)/(tu)=(3)/(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/mwvuc0y1j0zlelag3wthpe0m6dp9bghuxq.png)
Equating the third and 4th equations, and substituting for td, we have
![(w+e)tu=d=(w-e)(3)/(2)tu\\\\e\left(1+(3)/(2)\right)=w\left((3)/(2)-1\right)\qquad\text{divide by $tu$,rearrange}\\\\5e=w\qquad\text{divide by $(1)/(2)$}](https://img.qammunity.org/2019/formulas/mathematics/high-school/kfewws86k9sefcu36vpm2d5fq4hug8fc10.png)
Solving the first equation for tu and substituting into the third equation, we get
![d=(w+e)(60)/(w)\\\\d=((5e+e)60)/(5e)=(360e)/(5e)\\\\d=72](https://img.qammunity.org/2019/formulas/mathematics/high-school/e7gto3lajsp94biiqm47yq40khq27vd9e7.png)
The number of steps between floors is 72, which is the number she would count if the escalator were not moving.