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How many moles do 5.62 x 1023 formula units of sodium hydroxide constitute?

0.934 moles

1.07 moles

3.38 moles

3.38 x 1047 moles

User Kyau
by
4.7k points

2 Answers

3 votes

Answer:


5.62* 10^(23) formula units of sodium hydroxide constitutes 0.934 moles.

Step-by-step explanation:

Number of molecules of sodium hydroxide =
N=5.62* 10^(23) molecules

Moles of sodium hydroxide = n


N=n* N_A


N_A=6.022* 10^(23) mol^(-1)


5.62* 10^(23)=n* 6.022* 10^(23) mol^(-1)

n = 0.934 moles

So,
5.62* 10^(23) formula units of sodium hydroxide constitutes 0.934 moles.

User Rony Nguyen
by
5.0k points
4 votes

Answer: -

0.934 moles constitute 5.62 x 1023 formula units of sodium hydroxide.

Explanation: -

6.02 x 10²³ NaOH formula units are present in 1 mole of sodium hydroxide according to Avogadro's Law.

5.62 x 10²³ NaOH formula units are present in
( 1 mole x 5.62 x 1023)/(6.02 x 1023)

= 0.934 moles of NaOH

User Laurent Etiemble
by
4.9k points