Question

Write the equation of a line in slope-intercept form that is perpendicular to the line y = 3/5 = 1 and passes through the point (-9, 4).

Answer 1

The slope of the line
`y=(3)/(5) x-1` is
`m=(3)/(5)`.

The line perpendicular to the above line has slope
`-(1)/(m) =-(5)/(3)`

Its equation is
`y=-(5)/(3) x+c`. Since this line passes through,
`(-9,4)`,

`4=-(5)/(3) )(-9)+c\\ c=-11`

Thus the equation of the line in slope intercept form is
`y=-(5)/(3) x-11`