This literally is half an equilateral triangle, a 30/60/90 triangle, the biggest cliche in trigonometry. You should memorize that the sides are in ratio
; then
![x = 16/2 = 8](https://img.qammunity.org/2019/formulas/mathematics/middle-school/dtu06v9obw2kg5qdil8s6dh5pzn81po19p.png)
![y = (16/2) √(3) = 8 \sqrt 3](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fnzui0g1rzoxb6rxo6ue6qxcuuhzkxpeup.png)
If we didn't know that, we could see that the altitude bisects the equilateral triangle's side, so 16=2x, i.e. x=8. Then
so
![y = √(16^2 - x^2) = √(16^2-8^2) = √(8^2(4) - 8^2) = 8 √(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/5ffssm7p01w0mh50yigtbptzfpge37p215.png)
Answer: x=8, y=8√3