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Multiply k+3/4k-2 * (12k^2 -3)

User Danharper
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1 Answer

4 votes

k+3/4k-2 * (12k^2 -3) would become k+3/2(2k-1)*3(2k+1)(2k-1).

Cross out the (2k-1)'s. Then we get k+3/2*6k+3 Now we just multiply

We then get, (6k^2+21k+9)/2

User Ahmet Recep Navruz
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