Question

Calculate the mass of oxygen in 350 g of Al(C2H3O2)3

A 57 grams
B 164.5 grams
C 39.17 grams
D 19.58 grams

Answer 1

The option B is a correct answer.

Step-by-step explanation:

Mass of aluminum ethoxide = 350 g

Moles of aluminum ethoxide =
`(350 g)/(204 g/mol)=1.7157 mol`

In 1 mole of aluminum ethoxide there are 6 moles of oxygen atom.

Then 1.7157 moles of aluminum ethoxide will have :

`1.7157 mol* 6 =10.294 mol`

Mass of 10.291 mole of oxygen atom = 10.294 mol 16 g/mol = 164.70 g[/tex]

The closest option to our answer is option B.

Hence, option B is correct answer.

Answer 2

Answer: -

164.5 grams of oxygen is present in 350 g of Al(C₂H₃O₂)₃

Explanation: -

Molar mass of Al(C₂H₃O₂)₃ = 27 x 1 + 12 x 6 + 1 x 9 + 16 x 6

= 204 g

Mass of oxygen present in 204 g of Al(C₂H₃O₂)₃ = 16 x 6 = 96 g

204 g of Al(C₂H₃O₂)₃ contains 96 g of oxygen.

350 g of Al(C₂H₃O₂)₃ contains
`(96 g oxygen x 350g Al (C2H3O2)3)/(204 gAl (C2H3O2)3)` of oxygen

= 164.5 grams

Thus 164.5 grams of oxygen is present in 350 g of Al(C₂H₃O₂)₃