Question

Two objects are placed on a table object one has a mass of 2 kg and a bottom surface area of 0.1m. Object to has a mass of 8 kg in the bottom surface area of 0.4 M. How much pressure does each object exerts on the table top.

Answer 1

Pressure exerted by each mass on the surface is given by

`P = (F)/(A)`

here F = force due to weight of object

A = area of the base

now for object 1 we will have

`P_1 = (2* 9.81)/(0.1)`

`P_1 = 196 Pa`

Similarly for object 2

`P_2 = (8*9.8)/(0.4)`

`P_2 = 196 Pa`

So by the above calculations we can say that pressure at the bottom surface will be same due to both blocks.