Question

suppose you know the base of a rectangle has a length of 12 inches and a diagonal has a lenght of 13 inches. find the area of the rectangle

Answer 1

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1. Find the missing leg:

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a² + b² = c²

12² + b² = 13²

b² = 13² - 12²

b² = 25

b = √25

b = 5

The missing leg is 5 inches.

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2. Find the area:

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Area = Length x Width

Area = 12 x 5 = 60 in²

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Answer: The area is 60 in².

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Answer 2

We are given

length=l=12inches

diagonal =d=13inches

Let's assume

width=w

so, firstly we need to find width

we know that length , width and diagonal form right angled triangle

so, we can use Pythagoras theorem

`d^2=l^2+w^2`

now, we can plug values

`13^2=12^2+w^2`

`w^2=25`

`w=5`

now, we can find area of rectangle

Area = length*width

`Area=l*w`

now, we can plug values

`Area=12*5`

`Area=60inch^2`.............Answer