Question

Sorry about that, thank you for pointing that out.

One month Dale rented 8 movies and 4 video games for a total of $49
. The next month he rented 3 movies and 2 video games for a total of
$21 . Find the rental cost for each movie and each video game.

Rental cost for each movie: $
Rental cost for each video game: $

Answer 1

Make two equations and solve using the substitution method.

8m + 4g = 49

3m + 2g = 21

where m = movies and g = video games

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Solve for g in the first equation.

8m + 4g = 49

Subtract 8m from both sides.

4g = 49 - 8m

Divide both sides by 4.

g = 49/4 - 2m

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Plug g into the second equation.

3m + 2(49/4 - 2m) = 21

Distribute 2 inside the parentheses.

3m + 24.5 - 4m = 21

Combine like terms.

-m + 24.5 = 21

Subtract 24.5 from both sides.

-m = -3.5

Divide both sides by -1.

m = 3.5

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Plug m into the first equation.

8(3.5) + 4g = 49

Distribute 8 inside the parentheses.

28 + 4g = 49

Subtract 28 from both sides.

4g = 21

Divide both sides by 4.

g = 5.25

____________________________________________________________

Rental cost for each movie: $ 3.50

Rental cost for each video game: $5.25

Answer 2

The rental cost for each movie would be $3.50, and the rental cost for each video game would be $5.25.

If movies are 'm', and video games are 'v', we can write a set of simultaneous equations to solve:

8m + 4v = 49

3m + 2v = 21

We can solve using elimination, and multiply the second equation by 2 to get 6m + 4v = 42, and then subtract:

8m + 4v = 49

- 6m + 4v = 42

= 2m = 7

÷ 2

m = 3.5

Now we can substitute in 'm' as 3.5 to find 'v':

(3 × 3.5) + 2v = 21

10.5 + 2v = 21

- 10.5

2v = 10.5

÷ 2

v = 5.25

I hope this helps!