Question

(please show your answer. thank you)

Your company makes game parts using 3-D printers. One customer wants a circular game coin that is 2.0 centimeters across and 0.5 centimeters thick, as shown below. You need to estimate the amount of plastic you will need for each batch of 50 coins. How many cubic centimeters is that, rounded up if necessary to be a multiple of 10 cubic centimeters?

Answer 1

The correct option is: A. 80 cm³

Step-by-step explanation

Diameter of the coin,
`d= 2.0` cm.

So, the radius,
`r= (d)/(2) = (2.0)/(2) = 1.0` cm.

As the coin is circular, so..

Area of each circular surface,
`A= \pi r^2 = \pi (1.0)^2 = \pi` cm²

Now for finding the amount of plastic for making each coin, we will find the Volume of each coin first.

As the thickness (
`h`) of the coin is 0.5 cm, so Volume of each coin,

`V= A*h \\\\= \pi*0.5 \\\\= 3.14159... * 0.5 \\\\ = 1.5707963... cm^3`

As you need to make a batch of 50 coins, so the total volume of 50 coins
`= (1.5707963...*50 )= 78.53981... = 80` [Rounded up to the nearest multiple of 10 cm³]

So, the amount of plastic you will need for making a batch of 50 coins is 80 cubic centimeter.