A2+5a+6=0 {a}^(2) + 5a + 6 = 0

Question

A2+5a+6=0

`{a}^(2) + 5a + 6 = 0`

Answer 1

You did a good job of sharing this quadratic equation in proper symbolic notation, but you haven't yet shared the instructions for this problem.

I will assume that you are to find the roots / zeros of a^2+5a+6=0. Factoring results in (a+3)(a+2)= 0, from which we deduce that a = -3 and a = -2.

The solution set is {-3, -2}.

Answer 2

we are given

`a^2+5a+6=0`

we can use factoring formula

`a^2-(m+n)a+mn=(a-m)(a-n)`

we can compare

and we get

`m+n=-5`

`mn=6`

now, we can solve for m and n

and we get

`m=-3 , n=-2`

now, we can use formula

and we get

`a^2+5a+6=(a+3)(a+2)`

now, we can set it equal to 0

`a^2+5a+6=(a+3)(a+2)=0`

`(a+3)=0`

`a=-3`

`a+2=0`

`a=-2`

so, we will get

`a=-2,a=-3`.............Answer