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A2+5a+6=0

{a}^(2) + 5a + 6 = 0

User Arryph
by
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2 Answers

2 votes

You did a good job of sharing this quadratic equation in proper symbolic notation, but you haven't yet shared the instructions for this problem.

I will assume that you are to find the roots / zeros of a^2+5a+6=0. Factoring results in (a+3)(a+2)= 0, from which we deduce that a = -3 and a = -2.

The solution set is {-3, -2}.

User Zsljulius
by
8.5k points
5 votes

we are given


a^2+5a+6=0

we can use factoring formula


a^2-(m+n)a+mn=(a-m)(a-n)

we can compare

and we get


m+n=-5


mn=6

now, we can solve for m and n

and we get


m=-3 , n=-2

now, we can use formula

and we get


a^2+5a+6=(a+3)(a+2)

now, we can set it equal to 0


a^2+5a+6=(a+3)(a+2)=0


(a+3)=0


a=-3


a+2=0


a=-2

so, we will get


a=-2,a=-3.............Answer

User Mustafabar
by
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