Question

Solve for di... 1/f = 1/do + 1/di

Answer 1

we are given

`(1)/(f) =(1)/(d_0) +(1)/(d_i)`

we can solve for di

so, firstly we will isolate di

`(1)/(f)-(1)/(d_0) = (1)/(d_i)`

`(1)/(d_i)=(1)/(f)-(1)/(d_0)`

now, we can simplify right side by taking common denominator

`(1)/(d_i)=(d_0)/(fd_0)-(f)/(fd_0)`

`(1)/(d_i)=(d_0-f)/(fd_0)`

now, we can inverse them to find di

`d_i=(fd_0)/(d_0-f)`...............Answer

Answer 2

Mirror Equations:

Concave Mirror Equation Formula :

1/f = 1/d0 + 1/di

Where, f - Focal length, di - Image distance, d0 - Object distance.

Solve:

Solution: 1/f = 1/do + 1/di ==> di = fdo/(do-f)

Solve for di: 1/f = 1/do + 1/di

Step 1: get the, 1/di by itself:

Subtract both sides by 1/do:

1/f - 1/do = 1/do + 1/di - 1/do

= 1/di = 1/f - 1/do.

Find Lowest Common Multiple (LCM.). ==> FDO

1/di = do/fdo - f / fdo

1/di = (do -f) / fdo

Answer: di = fdo / (do-f)

Therefore, Your answer would be, di = fdo / (do-f)

Hope that helps!!!! : )