(1/x-2)-(1/x+2)= (A)=0 (B)=-(1/4) (C)=(-4/x^(2)) (D)=(4/x^(2)-4) (E)=(2x/x^(2)-4) show work

asked Jul 3, 2019 86.4k views

5 votes

(1/x-2)-(1/x+2)=

(A)=0
(B)=-(1/4)
(C)=(-4/x^(2))
(D)=(4/x^(2)-4)
(E)=(2x/x^(2)-4)
show work

4.6k points

Please log in or register to add a comment.

2 votes

$(1)/(x-2)-(1)/(x+2)=(x+2)/((x-2)(x+2))-(x-2)/((x-2)(x+2))\\\\=((x+2)-(x-2))/((x-2)(x+2))=(x+2-x+2)/((x-2)(x+2))=(4)/(x^2-4)\to(D)$

Used:
a^2-b^2=(a-b)(a+b)

Answer: (D)=(4/x^(2)-4)

Mihir Mathuria answered Jul 9, 2019

5.2k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.9m questions

7.7m answers