Question

Mrs. rifkin has 84 oranges. 24 of her oranges were rotten. the rest were either ripe or unripe. there were 18 more ripe oranges than unripe oranges. find the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.

Answer 1

39:24:21

Explanation:

rotten = 24

ripe = x+18

unripe = x

x+x+18+24=84 oranges

-24 -24

2x+18=60 oranges

-18 -18

2x=42 oranges

÷2 ÷2

x=21

rotten = 24

ripe = x +18 = 39

unripe = x = 21

The ratio would be

39:24:21

Answer 2

Alright, lets get started.

Suppose there were x unripe oranges.

there were 18 more ripe oranges than unripe oranges

Means number of ripe oranges = x + 18

There were 24 rotten oranges too.

So, the sum of all oranges will be =
`x + (x + 18) + 24`

So, the sum of all oranges will be =
`2 x + 42`

As per given in question, sum of total oranges are 84.

Hence making them equal

`2 x + 42 = 84`

Subtracting 42 from both sides

`2x + 42 - 42 = 84 - 42`

`2 x = 42`

Dividing 2 in both sides

`(2x)/(2) = (42)/(2)`

x = 21

Means number of unripe oranges = 21

Means number of ripe oranges = 21 + 18 = 39

Number of rotten oranges = 24

the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges =
`39 : 24 : 21` : Answer

Hope it will answer :)