Question

PLS HELP The perimeter of the rectangle below is 304ft. What is the value of a

Answer 1

Given the perimeter of the rectangle = 304 ft.

The length of the rectangle given = (9a+10) ft

width of the rectangle given = (8a+6)ft

We know that the formula to find the perimeter of the rectangle is

2(length + width)

So by placing the values of length and width of the rectangle in the formula we will get,

`2((9a+10)+(8a+6))`

=
`2(9a+10+8a+6)`

We will add like terms now. Here like terms means a with a and constant term with constant term. So we will add 9a and 8a and also 10 and 6.

`2(9a+8a+10+6)`

=
`2(17a+16)`

Now we will equate this perimeter with the perimeter given.

`2(17a+16) = 304`

Now we have to move 2 to the other side by dividing it to both sides.

`2(17a+16) /2 = 304/2`

`17a+16 = 304/2`

`17a+16 = 152`

We will move 16 now to the other side by subtracting it from both sides.

`17a+16-16 = 152 -16`

`17a = 152-16`

`17a = 136`

Now to find a, we have to move 17 to the other side by dividing it to both sides.

`17a/17 = 136/17`

`a = 136/17`

`a = 8`

So we have got the required answer.

The value of a = 8ft.